tolong bgt kak, pake cara makasi yaa
17. sin ½θ = ⅕√5
[tex] \sin\frac{1}{2} \alpha = \sqrt{ \frac{1 - cos \alpha }{2} } \\ (\frac{1}{5} \sqrt{5}) {}^{2} = (\sqrt{ \frac{1 - \cos \alpha }{2} } ) {}^{2} [/tex]
1/25. 5 = 1 - cos θ
⅕ = 1 - cos θ
cos θ = 1 - ⅕
cos θ = 5/5 - ⅕ = ⅘
cos θ = sa/mi, yang sa = 4, dan mi = 5
[tex](de) = \sqrt{(mi) {}^{2} - (sa) {}^{2} } \\ = \sqrt{5 {}^{2} - 4 {}^{2} } \\ = \sqrt{25 - 16} \\ = \sqrt{9} = 3[/tex]
sin θ = de/mi = ⅗
sin 2θ = 2 sin θ cos θ
= 2.⅗.⅘
= 24/25( C. )
[answer.2.content]
